In this video I go over another example on polar coordinates, and in this example I sketch the polar equation r = 2cosθ. This is the first part of a two part example question, the second which I will do in a later video is on converting this polar equation to Cartesian form. In this first part, I sketch this curve by finding several coordinates which have angles that we know the exact trigonometric ratios for. Graphing several of this points onto a polar coordinate system, the shape appears to be a circle (which indeed is). Also, I explain how if extend past the domain of the angle between 0 to pi, we simply just plot the same points again. Also for angles that are in the 2nd or third quadrant, I show that we end up getting a negative r value, and thus we move the distance backwards to, again, get the same points onto the circle. This is a really important example in understanding how to manually sketch polar equations, especially those involving trigonometry, so make sure to watch this video!
Download the notes in my video: https://1drv.ms/b/s!As32ynv0LoaIhulaAxdqyyJRly7wJg
View Video Notes on Steemit: https://steemit.com/mathematics/@mes/video-notes-polar-coordinates-example-6-part-1-sketching-a-circle
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