Lecture 9: Primitive Types: Initialization Solution

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Primitive type initalization problem statement

Initialize a 'char' data type named ‘letterY’ with the value ‘Y’

Primitive types initialization coding solution

char letterY = 'Y';

public class Lecture9 {
    public static void main(String[] args) {
        // TODO: Initialize a char data type named ‘letterY’ with the value ‘Y’
        System.out.print(letterY);
    }
}

Primitive Types initialization coding output

Y

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Hallo again, I am Marius from AlefTav Coding. In this lecture you will learn the solution to the initializaion coding exercise.

The coding exercise required you to Initialize a char data type named ‘letterY’ with the value ‘Y’. Please note it is an uppercase letter, Y. Looking at our expected solution, you use the Java pattern, dataType storageName = value. The problem statement says the data type must be char. Then, the storage name must be, letterY. Finally, the value you need to store is the single character, Y. This letter must be between single quotes, because that is how Java recognizes that a value is of data type char.

The solution code is this line, char letterY = 'Y'. I have here a class, Lecture9 with the usual main() method. This is after I have removed the TODO comment. As always, the semi-colon (;) ends a Java statement.

In this lecture you learned the solution to the initializaion coding exercise.

Next time we will look at using operators in Java.

This is Marius from AlefTav Coding. Till next time, KEEP CODING.

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