Today I did an experiment to test halogenide ions in solution. I've prepared four solutions of different halogenide salts (potassium iodide, sodium bromide, ammonium chloride and sodium fluoride). Then I've added a few drops of silver(I) nitrate solution into these halogenide solutions.
In the photo you can see the results of this experiment.
First one from the left was potassium iodide solution and you can see that yellow (greenish) precipitate is formed after reaction with silver(I) nitrate. Next one was sodium bromide solution and there pale yellow precipitate is formed. The third one was ammonium chloride solution where white precipitate was formed. The last one didn't react with silver(I) nitrate solution because silver(I) fluoride and sodium fluoride are soluble in water, so no precipitate can be formed. Because of that fluoride ions cannot be identified with silver(I) nitrate, but there are other reagents to identify fluoride ions.
