Python Programming Series # 5 - Logic-1

Hey Guys!!
This is in continuation to the Python Programming Series.

Before proceeding further, please visit these tutorials (link provided below), if you want to start from beginning.
Session 1
Session 2
Session 3
Session 4

Coding

Logic-1 > cigar_party

Question:
When squirrels get together for a party, they like to have cigars. A squirrel party is successful when the number of cigars is between 40 and 60, inclusive. Unless it is the weekend, in which case there is no upper bound on the number of cigars. Return True if the party with the given values is successful, or False otherwise.

Check for these cases:
cigar_party(30, False) → False
cigar_party(50, False) → True
cigar_party(70, True) → True

Solution:

def cigar_party(cigars, is_weekend):
    if is_weekend:
        print("True")
    else:
        if cigars >= 40 and cigars <= 60:
            print("True")
        else:
            print("False")
            
cigar_party(30, False) #→ False
cigar_party(50, False) #→ True
cigar_party(70, True) #→ True

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Logic-1 > date_fashion

Question:
You and your date are trying to get a table at a restaurant. The parameter "you" is the stylishness of your clothes, in the range 0..10, and "date" is the stylishness of your date's clothes. The result getting the table is encoded as an int value with 0=no, 1=maybe, 2=yes. If either of you is very stylish, 8 or more, then the result is 2 (yes). With the exception that if either of you has style of 2 or less, then the result is 0 (no). Otherwise the result is 1 (maybe).

Check for these cases:
date_fashion(5, 10) → 2
date_fashion(5, 2) → 0
date_fashion(5, 5) → 1

Solution:

def date_fashion(you, date):
    if you <= 2 or date <= 2:
        print("0")
    elif you >= 8 or date >=8:
        print("2")
    else:
        print("1")
        
date_fashion(5, 10) #→ 2
date_fashion(5, 2) #→ 0
date_fashion(5, 5) #→ 1

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Logic-1 > squirrel_play

Question:
The squirrels in Palo Alto spend most of the day playing. In particular, they play if the temperature is between 60 and 90 (inclusive). Unless it is summer, then the upper limit is 100 instead of 90. Given an int temperature and a boolean is_summer, return True if the squirrels play and False otherwise.

Check for these cases:
squirrel_play(70, False) → True
squirrel_play(95, False) → False
squirrel_play(95, True) → True

Solution:

def squirrel_play(temp, is_summer):
    if is_summer:
        if temp >= 60 and temp <= 100:
            print("True")
    else:
        if temp >= 60 and temp <= 90:
            print("True")
        else:
            print("False")
            
squirrel_play(70, False) #→ True
squirrel_play(95, False) #→ False
squirrel_play(95, True) #→ True

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Logic-1 > caught_speeding

Question:
You are driving a little too fast, and a police officer stops you. Write code to compute the result, encoded as an int value: 0=no ticket, 1=small ticket, 2=big ticket. If speed is 60 or less, the result is 0. If speed is between 61 and 80 inclusive, the result is 1. If speed is 81 or more, the result is 2. Unless it is your birthday -- on that day, your speed can be 5 higher in all cases.

Check for these cases:
caught_speeding(60, False) → 0
caught_speeding(65, False) → 1
caught_speeding(65, True) → 0

Solution:

def caught_speeding(speed, is_birthday):
    if is_birthday:
        if speed <= 65:
            print("0")
        elif speed >= 66 and speed <= 85:
            print("1")
        elif speed >= 86:
            print("2")
    else:
        if speed <= 60:
            print("0")
        elif speed >= 61 and speed <= 80:
            print("1")
        elif speed >= 81:
            print("2")
        
    
caught_speeding(60, False) #→ 0
caught_speeding(65, False) #→ 1
caught_speeding(65, True) #→ 0

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Logic-1 > sorta_sum

Question:
Given 2 ints, a and b, return their sum. However, sums in the range 10..19 inclusive, are forbidden, so in that case just return 20.

Check for these cases:
sorta_sum(3, 4) → 7
sorta_sum(9, 4) → 20
sorta_sum(10, 11) → 21

**Solution: **

def sorta_sum(a, b):
    sum = a+b
    if sum >= 10 and sum <= 19:
        print("20")
    else:
        print(sum)
        
    
sorta_sum(3, 4) #→ 7
sorta_sum(9, 4) #→ 20
sorta_sum(10, 11) #→ 21

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Logic-1 > alarm_clock

Question:
Given a day of the week encoded as 0=Sun, 1=Mon, 2=Tue, ...6=Sat, and a boolean indicating if we are on vacation, return a string of the form "7:00" indicating when the alarm clock should ring. Weekdays, the alarm should be "7:00" and on the weekend it should be "10:00". Unless we are on vacation -- then on weekdays it should be "10:00" and weekends it should be "off".

Check for these cases:
alarm_clock(1, False) → '7:00'
alarm_clock(5, False) → '7:00'
alarm_clock(0, False) → '10:00'

Solution:

def alarm_clock(day, is_vacation):
    if is_vacation:
        if day == 0 or day == 6:
            print("\'10:00\'")
        else:
            print("\'10:00\'")
    else:
        if day == 0 or day == 6:
            print("\'10:00\'")
        else:
            print("\'7:00\'")
        
    
alarm_clock(1, False) #→ '7:00'
alarm_clock(5, False) #→ '7:00'
alarm_clock(0, False) #→ '10:00'

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Logic-1 > love6

Question:
The number 6 is a truly great number. Given two int values, a and b, return True if either one is 6. Or if their sum or difference is 6. Note: the function abs(num) computes the absolute value of a number.

Check for these cases:
love6(6, 4) → True
love6(4, 5) → False
love6(1, 5) → True

Solution:

def love6(a, b):
    sum = a + b
    diff = abs(a - b)
    
    if a == 6 or b == 6 or sum == 6 or diff == 6:
        print("True")
    else:
        print("False")
        
    
love6(6, 4) #→ True
love6(4, 5) #→ False
love6(1, 5) #→ True

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Logic-1 > in1to10

Question:
Given a number n, return True if n is in the range 1..10, inclusive. Unless outside_mode is True, in which case return True if the number is less or equal to 1, or greater or equal to 10.

Check for these cases:
in1to10(5, False) → True
in1to10(11, False) → False
in1to10(11, True) → True

Solution:

def in1to10(n, outside_mode):
        if outside_mode:
            if n <= 1 or n >= 10:
                print("True")
            else: 
                print("False")
        else:
            if n >= 1 and n <= 10:
                print("True")
            else:
                print("False")
    
in1to10(5, False) #→ True
in1to10(11, False) #→ False
in1to10(11, True) #→ True

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Logic-1 > near_ten

Question:
Given a non-negative number "num", return True if num is within 2 of a multiple of 10. Note: (a % b) is the remainder of dividing a by b, so (7 % 5) is 2. See also: Introduction to Mod

Check for these cases:
near_ten(12) → True
near_ten(17) → False
near_ten(19) → True

Solution:

def near_ten(num):
    mod_num = num % 10
    if mod_num <= 2:
        print("True")
    else:
        print("False")
        
    
near_ten(12) #→ True
near_ten(17) #→ False
near_ten(19) #→ False

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Stay tuned for next tutorial.... :)

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