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A.logπ₯ B.1 C.0 D.12logπ₯ E.2 Solve the inequality xlog100.1>log1010. A. x<-1 B. x<1 C. x>1 D. x>100 E. x>-1 If logπ+π= logπβlogπ , then p=β¦β¦β¦. A. p=q=1 B. p=π1βπ C. p=π21βπ D.
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