Geometric Series: Sum of x^n series = 1/(1 - x) if |x| is less than 1
In this video, I show that the infinite series x^n = x^0 + x^1 + x^2 + ... is just a geometric series, and converges if the absolute value of x is less than 1. By common convention, x^0 = 1, so the first term a is 1, and the common ratio is x, thus the sum is given by the formula 1/(1 - x).
RE: LeoThread 2026-06-18 19-59