In this video, we perform the integral of 3x2+8 / x3+4x with the f'(x)/f(x) rule...
We do this first by expressing the function as a quotient of 2 functions:
And realising that q'(x) = 3x^2 + 4, which is very similar to p(x) = 3x^2 + 8.
If we express p(x) as p(x) = 3x^2 + 4 + 4, then the quotient becomes...
p(x)/q(x) = 3x^2 + 4 / x^3+4x + 4 / x^3+4x = q'(x) / q(x) + 4 / x^3+4x
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