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Conjecture on RSA factorization O(k)
Esempio
N=703
(703-3)/4=175
[175-(4n+1)]/3-[175-(4n+1)]/3-(2n+1)]/3=Z(4n+1)
,
4[175-(4n+1)]/3+1=(4Z+1)(4n+1)
https://steemit.com/cryptography/@logicalworld/conjecture-on-rsa-factorization-in-2-i-1-log-2-i-1-n