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Conjecture on RSA factorization O(k)

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Conjecture on RSA factorization O(k)

logicalworld(25)

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2018-09-18 11:57

Conjecture on RSA factorization O(k)

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N=703

(703-3)/4=175

[175-(4n+1)]/3-[175-(4n+1)]/3-(2n+1)]/3=Z(4n+1)
,
4[175-(4n+1)]/3+1=(4Z+1)(4n+1)

https://steemit.com/cryptography/@logicalworld/conjecture-on-rsa-factorization-in-2-i-1-log-2-i-1-n

2018-09-18 11:57

logicalworld(25)

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