RE: RE: JavaScript开发笔记
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RE: JavaScript开发笔记

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//在数组后面添加
this.lists.push(car)

//按id删除数组对象
arr.splice(0,1),arr.splice(1,2)2
arr.splice(arr.findIndex(item => item.id === 8), 1)

this.lists.pop(id)

//合并两个数组 posts合并posts2成为一个新的数组
let posts = posts.concat(posts2);

//颠倒数组  arr.reverse()
reverse()
使reverse()reverse
data= [{name:'tian', age:20},
      {name:'hello', age:30},
      {name:'today', age:50}
      ]
data.reverse()
console.log(data)
  [{name:'today', age:50},
  {name:'hello', age:30},
  {name:'tian', age:20}
  ]


//判断数组为空
let data = []
if(data == false){
  //data为空数组时,要执行的代码
  console.log(169, data)
}
 data.length == 0

//数组切片
slice() 
(),slice(start,end)(start,end),,endend

let fruits = ["Banana", "Orange", "Lemon", "Apple", "Mango"]
let citrus = fruits.slice(0, 3) //从0到3,不包括3,即[0: "Banana" 1: "Orange"2: "Lemon"]
let left = fruits.slice(3) //从3开始的剩余部分,即[0: "Apple" 1: "Mango"]

//获取数组最后四个元素
let heroes=["李白",'蔡文姬','韩信','赵云','甄姬','阿珂','貂蝉','妲己']
let s = heroes.slice(-4)
console.log(156, s) //[ '甄姬', '阿珂', '貂蝉', '妲己' ]

//数组去重方法1
ES6Set
Set
function unique5(arr){
  var x = new Set(arr)
 return [...x]
}

//数组去重方法2
let json1=[
    {id:1,name:"aaa"},
    {id:2,name:"bbb"},
    {id:3,name:"ccc"},
] 
let json2=[
    {id:1,name:"aaa"},
    {id:2,name:"bbb"},
    {id:4,name:"ddd"},
]
 
let json = json1.concat(json2) //两个数组对象合并
let newJson = [] //盛放去重后数据的新数组
for(let item1 of json){  //循环json数组对象的内容
    let flag = true  //建立标记,判断数据是否重复,true为不重复
    for(let item2 of newJson){  //循环新数组的内容
        if(item1[1].block==item2[1].block){ //让json数组对象的内容与新数组的内容作比较,相同的话,改变标记为false
            flag = false
        }
    }
    if(flag){ //判断是否重复
        newJson.push(item1)//不重复的放入新数组.新数组的内容会继续进行上边的循环。
    }
}
console.log("newJson",newJson)


//按升序对数组中的数字进行排序:
var points = [40, 100, 1, 5, 25, 10]
points.sort((a, b) => {return a-b})

//按降序对数组中的数字进行排序:
var points = [40, 100, 1, 5, 25, 10]
points.sort((a, b) => {return b-a})
@lemooljiang: //在数组后面添加 | Ecency