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Interesting that also you end up with an other series to solve, and exactly the same series I got too. Probably with (n3)/(2n) one get two "sub" series to solve and so on.
Interesting that also you end up with an other series to solve, and exactly the same series I got too. Probably with (n3)/(2n) one get two "sub" series to solve and so on.
RE: Math Contest #26 Alternative Solution