HEX game will be all about HEXADECIMAL numbers, and (sometimes) about the number SIX (6)
Choose the random HEX, see what HASH function has to say, and win LEO Booms and LEO voting power.
The HEX game works like this:
Users create their participation "tickets", by making a random Leothread comment under 
These Entry gateways are created once a day, every day, at random times.
Entry gateways can be published in Leothreads by 
Gateway can be recognised by clear note "HEXGAME JUNE xx" on it, displayed on some HEXAGONAL background picture
Participant's ticket creation thread-posts can contain any info, be any length, but there must be TWO important elements present in it, in order for it to become a valid "ticket" :
A typical ticket claiming post may be like this: "bal bla bla...nonsense...7 #hexgame", or "bls bla bla...bullshit...F #hexgame", or just simple "A #hexgame"
All participants can create as many "tickets" as they want - there is no limits.
The important reference element in your ticket is its mark - that 1 character HEX number.
As the entries accumulate, created tickets will be grouped in a SIX unit long branches, and their corresponding HEX digits will form the argument for HASHING calculation.
The output of the SHA1 hash will determine which tickets are wining.
One branch probably will be always formed from the first SIX TIER-1 entries, placed directly under gateway. (see example picture below)
These HEX marks from the tickets will be put together chronologically, to form a 6 HEX digit string for hashing.
Repeating participant entries in the SAME Branch will be always ignored (see BRANCH2 and BRANCH4 examples)
The output of the hash function (SHA1) is always a string of 40 HEX numbers. The FIRST SIX characters of this output will determine, which HEX marks are winning in that particular branch
1st digit - 100% BOOM by a ~1 MLN LEO power
2nd digit - 50% upvote
3rd digit - 33.33% upvote
4th digit - 25% upvote
5th digit - 20% upvote
6th digit - 16.67% upvote
Like in the example shown, TIER-1 Branch-4 is 6 tickets with marks 8632FA, and sha1(8632FA)=fd6239ccaf81b4cf88754c3e940cddbc8665004f
Winning tickets are fd6239. As we see, only 4 reall winners this time:
f-100%
d- no entry
6-33.3% UV
2-25% UV
3-20% UV
9- no entry
User-3 had one repeating entry in TIER-1, so it was skipped, and first 6 non-repeating tickets were taken for this hashing.
This way (in the example above) a vertical branches #1, #2 and #3 could been formed.
Again, only NON-repeating tickets in the same branch will be used.
In case some intensive comment editing will be noted from a particular participants (cheat attempt) - additional 7th SALT character maybe used, before the SHA1 hash is calculated.
(anti-cheating measure)
The maximum possible Branch quantity each day may reach 1 Horizontal (TIER-1) and up to SIX (6) vertical branches.
Once the hashing of 6 entries is calculated - the outcome post will be posted by GATEWAY creator.
Tickets can be created up to 7 days after gateway is posted ( provided there are still potential winning space left). NO RUSH.
Once every week all the 100% BOOM winners (if there are 3 or more) will participate in a last 7 day Super-Hex prize drawings (random draw).
Super-HEX prize ( #shexprize ) will be a 3 week delegation of 20000 LEO power
20K LEO ~power in 21 day can produce about ~120 LEO in curation rewards. And HALF of that will be yours, as a curator
So you may guess, what tactics is the best to win the most?
I think it is obvious, that as long as TIER-1 comment quantity is still below 6 - this is a good place to drop your ticket.
This way you get a chance to participate in 2 branches with just one entry (1 horizontal and 1 vertical)
Then comes the time for vertical branches. Take part in as many as you want ... and can.
But avoid creating repeating entries in the same branch, as it brings no benefit anyway
Good luck.
