No the door that you picked still has a 1/3 chance of being correct while the other door is 1/2.
At the end of the simulation:

• one door has a 1/2 chance of success (the one you can switch to)
• one door has a 1/3 to win (the one you picked)
• the last door has a 0% chance to win due to elimination by the host

Which is very weird because the odds don't add up to 100% because they were changed mid flight.

Many readers of Savant's column refused to believe switching is beneficial and rejected her explanation. After the problem appeared in Parade, approximately 10,000 readers, including nearly 1,000 with PhDs, wrote to the magazine, most of them calling Savant wrong.[4] Even when given explanations, simulations, and formal mathematical proofs, many people still did not accept that switching is the best strategy.[5] Paul Erdős, one of the most prolific mathematicians in history, remained unconvinced until he was shown a computer simulation demonstrating Savant's predicted result.[6]

https://en.wikipedia.org/wiki/Monty_Hall_problem

Rereading it now just to make sure I have it right...
And it looks like switching does indeed give you 2/3 chance to win.
All the odds do in fact add up to 100%.