Math Easy Solutions, here’s the corrected version: the setup was a standard electrolysis cell with a palladium cathode (-), platinum anode (+), heavy water (D₂O), and typically lithium deuteroxide (LiOD) dissolved in the heavy water as the electrolyte, inside a Dewar/calorimetric vessel rather than “surrounded inside a bath of water” as a defining feature of the core cell Wikipedia, Understanding Science. “Lithium deuterium oxide” is the wrong name; it should be lithium deuteroxide, and an electrolyte is more precisely a substance that dissociates into ions in solution and allows current to flow Britannica, Wikipedia. The anode is where oxidation occurs, but oxidation does not mean “typically by gaining oxygen” here; at the platinum anode, water/deuteroxide is oxidized to release oxygen gas, while the platinum mainly serves as an inert electrode rather than “gaining oxygens” itself Chem LibreTexts/11%3A_Electrochemistry/11.07%3A_Electrolysis), New Energy Times. At the cathode, deuterium ions are reduced, some deuterium gas can evolve, and some deuterium is absorbed into the palladium lattice; palladium does not simply “absorb electrons” as a stored ingredient of the reaction Wikipedia, Understanding Science.