I would say you split 1/(x*(x+3))=1/(3*x)-1/(3*(x+3))=1/3*(1/x-1/(x+3)). Now if you sum over these terms everything cancels out except 1/3*(1/1+1/2+1/3)=11/18

tonimontana Good lucky everyone! :)

Do we even know that the zeros of the truncated sum have anything to do with the zeros of the real function? Like say you have Then f is 0 but all the finite sums have no zeros.

tonimontana. Good luck everyone!

I made another one that works a bit better. The real part seems to always cross the x-axis at a zero(See picture). So the zeros of the real part can easily befound by bisection. Then just check if the

Altough I am not sure if 14.13 even is a zero :)

I am not sure lol. I just looked a the plot and guessed where the first zero is. The convergence is not very good but I got something like 14.13. import matplotlib.pyplot as plt def f(y): s=complex(0.5,y)

I am really looking forward to future events! I had good fun on this one ;)

I have a list with all the accounts that have cast a vote in the last 24 hours. It is about 32.5k. You can load it with file = open("accounts.txt","r") itemlist=file.readlines() I hope

If you just do algebra and set x=1-1+1... you get 1-x=1-1+1-1=x or x=1/2. So I would probably go with 1/2 :D

I had a lot of fun playing over the weekend and got 66 wins.

Just started playing gods unchanied let's see how it goes :)

One thing I would like to see is a chat replay feature for the VOD. Chat interaction is pretty important when livestreaming. And without a chat replay it is a little hard to follow sometimes when watching

I tried plotting it :D

Thanks!

Wait I think x=t with odd t and y=(1-t^2)/2 z=(1+t^2)/2

x=0 ,y=0,z=-0

5.You can check if a number is divisible by a number d with a n-digit sum if there some m such that m*d=10^n-1. So for 11 it would be 9*11=99. 2.And this even works almost the same if you can find a multiple

x=(1±sqrt(5))/2 , y=1 This is way harder than expected so I just started guessing. y=1 is the only way I could get a solution.

I scrolled down too far and saw the answers so I didn't feel like participating anymore because it would have been cheating. But there odds to win here are much better than a lot of the other contest even