RE: RE: @steem-raffle drawing 59
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RE: @steem-raffle drawing 59

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8y

The block in which the above post is included has a merkle root of 346f13287de067f156a42b41c562751d1a2d610d.
The last two digits of this root are used to determine if there is a winner. Ending in 0 gives an upvote and ending in 00 means the jackpot was cracked. The remaining digits determine which ticket wins. To do this we compute the residual after dividing the root by the number of virtual tickets. In this case this would be:
346f13287de067f156a42b41c562751d1a2d61 = 1169314733249697722224513973743875800123977057 in base 10. The residual after dividing by the number of shares (920) is 657. Therefore ticket number 657 would win.

This time the root does not end in 0 and thus there is no winner in this drawing. The post will be upvoted to increase the jackpot