RE: RE: @steem-raffle drawing 27
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RE: @steem-raffle drawing 27

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The block in which the above post is included has a merkle root of 1a2556cd99569d63a2115e6051c1e489f92a5b2f.
The last two digits of this root are used to determine if there is a winner. Ending in 0 gives an upvote and ending in 00 means the jackpot was cracked. The remaining digits determine which ticket wins. To do this we compute the residual after dividing the root by the number of virtual tickets. In this case this would be:
1a2556cd99569d63a2115e6051c1e489f92a5b = 583072067312743843659666941445190316361067099 in base 10. The residual after dividing by the number of shares (1093) is 139. Therefore ticket number 139 would win.

This time the root does not end in 0 and thus there is no winner in this drawing. The post will be upvoted to increase the jackpot