RE: RE: @steem-raffle drawing 22
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RE: @steem-raffle drawing 22

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The block in which the above post is included has a merkle root of d6cb923176978384d528d19e22e44b63cf8cdcff.
The last two digits of this root are used to determine if there is a winner. Ending in 0 gives an upvote and ending in 00 means the jackpot was cracked. The remaining digits determine which ticket wins. To do this we compute the residual after dividing the root by the number of virtual tickets. In this case this would be:
d6cb923176978384d528d19e22e44b63cf8cdc = 4790093013503207025990717475373046137275518172 in base 10. The residual after dividing by the number of shares (1013) is 960. Therefore ticket number 960 would win.

This time the root does not end in 0 and thus there is no winner in this drawing. The post will be upvoted to increase the jackpot