RE: RE: @steem-raffle drawing 11
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RE: @steem-raffle drawing 11

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8y

The block in which the above post is included has a merkle root of 76252bfb82beb017b9c57a92e8268ec7ad6d6753.
The last two digits of this root are used to determine if there is a winner. Ending in 0 gives an upvote and ending in 00 means the jackpot was cracked. The remaining digits determine which ticket wins. To do this we compute the residual after dividing the root by the number of virtual tickets. In this case this would be:
76252bfb82beb017b9c57a92e8268ec7ad6d67 = 2634726054462959403128515853836021636356992359 in base 10. The residual after dividing by the number of shares (1054) is 965. Therefore ticket number 965 would win.

This time the root does not end in 0 and thus there is no winner in this drawing. The post will be upvoted to increase the jackpot