RE: RE: ARITHMETICS AND ME || the unexpected friendship.
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RE: ARITHMETICS AND ME || the unexpected friendship.

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1y

😂😂😂 this made me laugh really hard and you even made me want to give it a try
but when I looked

If x=0 y=10 find the values of z
2z+5xz+2y

that is an expression not an equation. For it to be an equation and solvable, it has to be = 0 or something

But i understand you, I was also there but trust me if you can take your time to study it from the basics you'll master the monster.

Now let me just go ahead and solve this since you've brought it to my comment

Equating it to zero
We have:
2z+5xz+2y = 0
Now since we're looking for z and it's attached to one of the known variable we will look for a way to separate them.

z(2+5x) = -2y
Make z subject of formula
Z =-2y / (2+5x)

Now substitute x=0 And y=10 into the equation

z = -2(10) / (2+5(0))

Z = -10/2
Therefore,
The value of Z should be -5

😂

@protokkol: 😂😂😂 this made | Ecency