<?xml version="1.0" encoding="UTF-8"?><rss xmlns:dc="http://purl.org/dc/elements/1.1/" xmlns:content="http://purl.org/rss/1.0/modules/content/" xmlns:atom="http://www.w3.org/2005/Atom" version="2.0"><channel><title><![CDATA[RSS Feed]]></title><description><![CDATA[RSS Feed]]></description><link>https://ecency.com</link><image><url>https://ecency.com/logo512.png</url><title>RSS Feed</title><link>https://ecency.com</link></image><generator>RSS for Node</generator><lastBuildDate>Sat, 10 Oct 2026 19:53:56 GMT</lastBuildDate><atom:link href="https://ecency.com/@mrmarcok/rss" rel="self" type="application/rss+xml"/><item><title><![CDATA[Solving Simultaneous Equations - Elimination]]></title><description><![CDATA[Solving simultaneous equations is the concept of solving for two unknown variables within an equation. This is the basis for determining the intersection between two graphs which is used in practical contexts]]></description><link>https://ecency.com/@mrmarcok/solving-simultaneous-equations-elimination</link><guid isPermaLink="true">https://ecency.com/@mrmarcok/solving-simultaneous-equations-elimination</guid><category><![CDATA[math]]></category><dc:creator><![CDATA[mrmarcok]]></dc:creator><pubDate>Sun, 14 Apr 2019 11:27:09 GMT</pubDate><enclosure url="https://i.ecency.com/p/S5Eokt4BcQdk7EHeT1aYjzebg2hC7hkthT45eGPsqizpezuAZ33x5gn5hq7zfjqh4E7TnWr?format=match&amp;mode=fit" length="0" type="false"/></item><item><title><![CDATA[Solving Simultaneous Equations - Substitution]]></title><description><![CDATA[Solving simultaneous equations is the concept of solving for two unknown variables within an equation. This is the basis for determining the intersection between two graphs which is used in practical contexts]]></description><link>https://ecency.com/@mrmarcok/solving-simultaneous-equations-substitution</link><guid isPermaLink="true">https://ecency.com/@mrmarcok/solving-simultaneous-equations-substitution</guid><category><![CDATA[math]]></category><dc:creator><![CDATA[mrmarcok]]></dc:creator><pubDate>Sun, 14 Apr 2019 11:20:24 GMT</pubDate><enclosure url="https://i.ecency.com/p/S5Eokt4BcQdk7EHeT1aYjzebg2hC7hkthT45ePwjZM6Xkh1R4FS2XWcBbw7qTsy2sgfoDyQ?format=match&amp;mode=fit" length="0" type="false"/></item><item><title><![CDATA[Sketching Half-Planes]]></title><description><![CDATA[A half-plane comes from an inequation. We still sketch a linear graph very similarly for half-planes, but from there ,we determine which region we need to shade...]]></description><link>https://ecency.com/@mrmarcok/sketching-half-planes</link><guid isPermaLink="true">https://ecency.com/@mrmarcok/sketching-half-planes</guid><category><![CDATA[math]]></category><dc:creator><![CDATA[mrmarcok]]></dc:creator><pubDate>Sun, 14 Apr 2019 11:13:36 GMT</pubDate><enclosure url="https://i.ecency.com/p/S5Eokt4BcQdk7EHeT1aYjzebg2hC7hkthT45dvCc1G7hdxMrX8nd4wSLud41VEdWSpPM4Fp?format=match&amp;mode=fit" length="0" type="false"/></item><item><title><![CDATA[Working With Parallel And Perpendicular Lines]]></title><description><![CDATA[When two linear graphs are parallel, they have the same gradient. When two linear graphs are perpendicular (at 90 degrees), if we multiply the two gradients, the result is -1. These facts allow us to carry]]></description><link>https://ecency.com/@mrmarcok/working-with-parallel-and-perpendicular-lines</link><guid isPermaLink="true">https://ecency.com/@mrmarcok/working-with-parallel-and-perpendicular-lines</guid><category><![CDATA[math]]></category><dc:creator><![CDATA[mrmarcok]]></dc:creator><pubDate>Sun, 14 Apr 2019 10:58:03 GMT</pubDate><enclosure url="https://i.ecency.com/p/S5Eokt4BcQdk7EHeT1aYjzebg2hC7hkthT45ePZwdbxjyK6cj6uzezL55hHGiiHuv254xAA?format=match&amp;mode=fit" length="0" type="false"/></item><item><title><![CDATA[Application of the Length of A Segment]]></title><description><![CDATA[To find the length of a segment, we use Pythagoras' Theorem. However sometimes, we are given the length of a segment and the co-ordinates of one end. We are then expected to determine the co-ordinates]]></description><link>https://ecency.com/@mrmarcok/application-of-the-length-of-a-segment</link><guid isPermaLink="true">https://ecency.com/@mrmarcok/application-of-the-length-of-a-segment</guid><category><![CDATA[math]]></category><dc:creator><![CDATA[mrmarcok]]></dc:creator><pubDate>Sun, 14 Apr 2019 10:50:06 GMT</pubDate><enclosure url="https://i.ecency.com/p/S5Eokt4BcQdk7EHeT1aYjzebg2hC7hkthT45dtBz9F5fk9evwpSeHckV9jSNfaTEAsY9u4z?format=match&amp;mode=fit" length="0" type="false"/></item><item><title><![CDATA[Midpoint of A Segment]]></title><description><![CDATA[If we are given a segment, which is a piece of a linear graph, sometimes we may want to determine its midpoint...]]></description><link>https://ecency.com/@mrmarcok/midpoint-of-a-segment</link><guid isPermaLink="true">https://ecency.com/@mrmarcok/midpoint-of-a-segment</guid><category><![CDATA[math]]></category><dc:creator><![CDATA[mrmarcok]]></dc:creator><pubDate>Sun, 14 Apr 2019 10:44:21 GMT</pubDate><enclosure url="https://i.ecency.com/p/S5Eokt4BcQdk7EHeT1aYjzebg2hC7hkthT45e4jA5eBzDfK93FxDoyxoytJkZsR7efHzo18?format=match&amp;mode=fit" length="0" type="false"/></item><item><title><![CDATA[Determining A Linear Equation From Its Graph]]></title><description><![CDATA[If we are given a linear graph, we can determine the equation to make that graph. This is handy to make conclusions about data...]]></description><link>https://ecency.com/@mrmarcok/determining-a-linear-equation-from-its-graph</link><guid isPermaLink="true">https://ecency.com/@mrmarcok/determining-a-linear-equation-from-its-graph</guid><category><![CDATA[math]]></category><dc:creator><![CDATA[mrmarcok]]></dc:creator><pubDate>Sun, 14 Apr 2019 10:39:15 GMT</pubDate><enclosure url="https://i.ecency.com/p/S5Eokt4BcQdk7EHeT1aYjzebg2hC7hkthT45dy1gaj4XSy99kujRS2KDwDD1YUPkMXWnYuk?format=match&amp;mode=fit" length="0" type="false"/></item><item><title><![CDATA[Sketching Linear Equations - ax + by = c]]></title><description><![CDATA[If we don't have gradient or y-intercept, we can sketch a graph by determining x- and y-intercepts which are done by letting y or x equal zero respectively and then solving for the other variable...]]></description><link>https://ecency.com/@mrmarcok/sketching-linear-equations-ax-by-c</link><guid isPermaLink="true">https://ecency.com/@mrmarcok/sketching-linear-equations-ax-by-c</guid><category><![CDATA[math]]></category><dc:creator><![CDATA[mrmarcok]]></dc:creator><pubDate>Sun, 14 Apr 2019 10:34:06 GMT</pubDate><enclosure url="https://i.ecency.com/p/S5Eokt4BcQdk7EHeT1aYjzebg2hC7hkthT45eNnT8BXfQU1fXStTmsdv2aNbehiXNGTF8EA?format=match&amp;mode=fit" length="0" type="false"/></item><item><title><![CDATA[Sketching Linear Equations - y = mx + c]]></title><description><![CDATA[When given the gradient and y-intercept, use these to sketch the linear graph...]]></description><link>https://ecency.com/@mrmarcok/sketching-linear-equations-y-mx-c</link><guid isPermaLink="true">https://ecency.com/@mrmarcok/sketching-linear-equations-y-mx-c</guid><category><![CDATA[math]]></category><dc:creator><![CDATA[mrmarcok]]></dc:creator><pubDate>Sun, 14 Apr 2019 10:26:18 GMT</pubDate><enclosure url="https://i.ecency.com/p/S5Eokt4BcQdk7EHeT1aYjzebg2hC7hkthT45e6HbtaQB59jRduxo8LWxyPJ4ZJsWDHat19G?format=match&amp;mode=fit" length="0" type="false"/></item><item><title><![CDATA[Solving linear inequations]]></title><description><![CDATA[We solve linear inequations the same was as we solve linear equations. Just remember to flip the sign when multiplying or dividing by a negative number...]]></description><link>https://ecency.com/@mrmarcok/solving-linear-inequations</link><guid isPermaLink="true">https://ecency.com/@mrmarcok/solving-linear-inequations</guid><category><![CDATA[math]]></category><dc:creator><![CDATA[mrmarcok]]></dc:creator><pubDate>Sun, 14 Apr 2019 10:16:12 GMT</pubDate><enclosure url="https://i.ecency.com/p/S5Eokt4BcQdk7EHeT1aYjzebg2hC7hkthT45eQSjEKYENGrFRa2wytG6pwBoo8fdKF72meE?format=match&amp;mode=fit" length="0" type="false"/></item><item><title><![CDATA[Solving linear equations]]></title><description><![CDATA[To solve linear equations, think of it as a party. Your closest friends will stick around the longest. Same goes for solving linear equations. The numbers closest to the unknown variable remain in the]]></description><link>https://ecency.com/@mrmarcok/solving-linear-equations</link><guid isPermaLink="true">https://ecency.com/@mrmarcok/solving-linear-equations</guid><category><![CDATA[math]]></category><dc:creator><![CDATA[mrmarcok]]></dc:creator><pubDate>Sun, 14 Apr 2019 10:10:54 GMT</pubDate><enclosure url="https://i.ecency.com/p/S5Eokt4BcQdk7EHeT1aYjzebg2hC7hkthT45eJN1q3yvM9w52RJbuLzmM9jzN8CWXXbvTCS?format=match&amp;mode=fit" length="0" type="false"/></item><item><title><![CDATA[Adding and subtracting algebraic fractions]]></title><description><![CDATA[We add and subtract algebraic fractions the same way as numeric fractions. There is just a little more work involved...]]></description><link>https://ecency.com/@mrmarcok/adding-and-subtracting-algebraic-fractions</link><guid isPermaLink="true">https://ecency.com/@mrmarcok/adding-and-subtracting-algebraic-fractions</guid><category><![CDATA[math]]></category><dc:creator><![CDATA[mrmarcok]]></dc:creator><pubDate>Sun, 14 Apr 2019 10:02:33 GMT</pubDate><enclosure url="https://i.ecency.com/p/S5Eokt4BcQdk7EHeT1aYjzebg2hC7hkthT45eNR88hzuhJypnf8acXussAJuQTHsSMQWx5C?format=match&amp;mode=fit" length="0" type="false"/></item><item><title><![CDATA[Multiplying And Dividing Algebraic Fractions]]></title><description><![CDATA[This is how we multiply and divide algebraic fractions. We can apply the same method to numerical fractions but there is less work involved...]]></description><link>https://ecency.com/@mrmarcok/multiplying-and-dividing-algebraic-fractions</link><guid isPermaLink="true">https://ecency.com/@mrmarcok/multiplying-and-dividing-algebraic-fractions</guid><category><![CDATA[math]]></category><dc:creator><![CDATA[mrmarcok]]></dc:creator><pubDate>Sun, 14 Apr 2019 09:55:30 GMT</pubDate><enclosure url="https://i.ecency.com/p/S5Eokt4BcQdk7EHeT1aYjzebg2hC7hkthT45eB6jbTungC9JWRsWXFQ87K2vb1GinpDiCGn?format=match&amp;mode=fit" length="0" type="false"/></item></channel></rss>